Hey,

My apologies for the subject, but i didnt want to scare people away with something like "How good is your math" :-)

Let's move on to the exercise: Source: http://xkcd.com/135/

Imho the information of the top speed isn't necessary in this case, because you will be
caught before the raptor reaches 25m/s.
After 6sec the raptor has a speed of 24m/s and ran a distance of 84m (=4+8+12+16+20+24 or "\sum\limits_{k=1}^6 4k" for our latex-friends),
whereas you have only ran 36m (=6*6) plus the 40m (distance you started at) = 76m (=40+6*n)
So the solution is somewhere between 5sec and 6sec.
But there is another fact, that keeps me busy. If you replace the 40m with something
bigger (like 400m or 40km for those, who are athletically trained :p), the top speed of
the raptor will be a factor.
Anyone care to write down the solution process? :)


thx
matt

hmm... easy... I don't need to run as velociraptors are extinct!

:)

The formula for the velociraptor distance is:

X = 0.5(a)*(t^2)

a == acceleration = 6
t == seconds

so, after 6 seconds:
velociraptor speed is 24m/s, and distance is only 72m (not 84).

After 6 seconds:
velociraptor at 72m and 24m/s
Human at 76m and 6m/s.