The prize has apparently been redeemed by Tannath
The solution was :
step 1 : the riddle tells you the first group is the key to the cypher and the nature of the initial alphanumeric characters:
(c=consonnant, v= vowel, n = numerals )
cccc-nccn-nvcc-cccv
Step 2 : the key tells you Cs have been advanced by 2, Vs have been shifted back by 1 and Ns adavanced by 3
2222-3223-3(1)22-222(1)
Step 3 (optional) : reversing this allows you to deduce the Vernière cypher
CCCC-DCCD-DZCC-CCCZ
Step 4 -inputing the cypher and cyphered text into a Vernière solver
- or simply applying the shift obtained in (2) to the cythered text gives you the result
VBKB-4XV3-9AKC-PTTY
Tannath: Got it!
The code was VBKB-4XV3-9AKC-PTTY. I'll edit the post in a few minutes to explain step-by-step how you got there.
Thank you for the giveaway, had this in my wishlist. =)
Congratulations !